LeedCode-Reverse Integer
1.题目描述 Given a 32-bit signed integer, reverse digits of an integer. Example 1: Input: 123 Output: 321 Example 2: Input: -123 Output: -321 Example 3: Input: 120 Output: 21 2. 解法 很基础的做法，通过除法，取余找到每位的数字进行反转 public int reverse(int x) { long n = 0; while(x != 0) { n = n * 10 + x % 10; x = x / 10; } return (int)n==n? (int)n:0; } 运行结果：